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                    5.3.5 - Protective conductor impedance
 It has been shown in the previous sub-section 
                      how a low-impedance protective conductor will provide safety 
                      from shock in the event of a fault to earth. This method 
                      can only be used where it is certain that the shock victim 
                      can never be in contact with conducting material at a different 
                      potential from that of the earthed system in the zone he 
                      occupies. Thus, all associated exposed or extraneous parts 
                      must be within the equipotential zone (see 
                      {5.4}). When overcurrent protective devices are used 
                      as protection from electric shock, the protective conductor 
                      must be in the same wiring system as, or in close proximity 
                      to, the live conductors. This is intended to ensure that 
                      the protective conductor is unlikely to he damaged in an 
                      accident without the live conductors also being cut. {Figure 5.9} shows a method of measuring 
                      the resistance of the protective conductor, using a line 
                      conductor as a return and taking into account the different 
                      cross-sectional areas of the phase and the protective conductors. Fig 5.9 - Measurement 
                      of protective conductor resistance Taking the cross-sectional area of the 
                      protective conductor as Ap and that of the line 
                      (phase or neutral) conductor as Al , then 
                       
                        | Rp = resistance reading 
                          x | Al |   
                        |  | Al + Ap |            For example, consider a reading of 0.72 
                      Ohms obtained when measuring a circuit in the way described 
                      and having 2.5 mm² line conductors and a 1.5 mm² protective 
                      conductor. The resistance of the protective conductor is 
                      calculated from: 
                       
                        | Rp =  R x  | Al  
                             | = 0.72 x 2.5 | Ohms |   
                        |  | Al + Ap | 2.5 + 1.5 |  |   
                        |  |  |  |  |   
                        | =  | 0.72 x 2.5 | Ohms = | 0.45 Ohms |   
                        |  | 4.0 |  |  |  
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